Answer
1.4
Work Step by Step
We are given that $log_{b}3=.5$ and that $ log_{b}5=.7$.
The power property of logarithms tells us that $log_{b}x^{r}=r log_{b}x$ (where x and b are positive real numbers, $b\ne1$, and r is a real number).
Therefore, $log_{b}25= log_{b}5^{2}=2log_{b}5=2\times.7=1.4$.
