Answer
$log_{3}\frac{12}{z}$.
Work Step by Step
The quotient property of logarithms tells us that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$).
Therefore, $log_{3}12-log_{3}z= log_{3}\frac{12}{z}$.
