Answer
$\frac{1}{2}log_{5}y $
Work Step by Step
The power property of logarithms tells us that $log_{b}x^{r}=r log_{b}x$ (where x and b are positive real numbers, $b\ne1$, and r is a real number).
Therefore, $ log_{5}\sqrt y=log_{5}y^{\frac{1}{2}}= \frac{1}{2}log_{5}y $.
