Answer
$log_{5}2y^{2}$
Work Step by Step
The product property of logarithms tells us that $log_{b}xy=log_{b}x+log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$).
Therefore, $log_{5}2+log_{5}y^{2}= log_{5}(2\times y^{2})=log_{5}2y^{2}$.
