Answer
1.2
Work Step by Step
We are given that $log_{b}3=.5$ and that $ log_{b}5=.7$.
The product property of logarithms tells us that $log_{b}xy=log_{b}x+log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$).
Therefore, $log_{b}15= log_{b}3+ log_{b}5=.5+.7=1.2$.
