Answer
$log_{6}(x^{2}+x)$
Work Step by Step
The product property of logarithms tells us that $log_{b}xy=log_{b}x+log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$).
Therefore, $log_{6}x+log_{6}(x+1)= log_{6}(x\times(x+1))=log_{6}(x^{2}+x)$.
