Answer
$tan~x-\frac{sec^2x}{tan~x}=-cot~x$
Work Step by Step
$tan~x-\frac{sec^2x}{tan~x}=tan~x~\frac{tan~x}{tan~x}-\frac{sec^2x}{tan~x}=\frac{tan^2x-sec^2x}{tan~x}=\frac{tan^2x-(tan^2x+1)}{tan~x}=-\frac{1}{tan~x}=-cot~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 47
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