Answer
$sec^3x-sec^2x-sec~x+1=tan^2x(sec~x-1)$
Work Step by Step
Remember that:
$sec^2x=tan^2x+1$
$sec^2x-1=tan^2x$
$sec^3x-sec^2x-sec~x+1=sec^2x(sec~x-1)-1(sec~x-1)=(sec^2x-1)(sec~x-1)=tan^2x(sec~x-1)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 28
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