Answer
$sin^2x~sec^2x-sin^2x=sin^2x~tan^2x$
Work Step by Step
Pythagorean Identity:
$tan^2x+1=sec^2x$
$tan^2x=sec^2x-1$
$sin^2x~sec^2x-sin^2x=sin^2x(sec^2x-1)=sin^2x~tan^2x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 22
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