Answer
$\frac{sec^2x-1}{sec~x-1}=sec~x+1$
Work Step by Step
$\frac{sec^2x-1}{sec~x-1}=\frac{sec^2x-1^2}{sec~x-1}=\frac{(sec~x+1)(sec~x-1)}{sec~x-1}=sec~x+1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 23
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