Answer
$3~sin^2x-5~sin~x-2=(3~sin~x+1)(sin~x-2)$
Work Step by Step
$3~sin^2x-5~sin~x-2=3~sin^2x-6~sin~x+sin~x-2=$
$=3~sin~x~(sin~x-2)+1~(sin~x-2)=(3~sin~x+1)(sin~x-2)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 29
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