Answer
$sec^4x-tan^4x=sec^2x+tan^2x$
Work Step by Step
Remember that:
$sec^2x=tan^2x+1$
$sec^2x-tan^2x=1$
$sec^4x-tan^4x=(sec^2x)^2-(tan^2x)^2=(sec^2x+tan^2x)(sec^2x-tan^2x)=(sec^2x+tan^2x)(1)=sec^2x+tan^2x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 26
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