Answer
$cos(\frac{\pi}{2}-x)sec~x=tan~x$
Work Step by Step
$cos(\frac{\pi}{2}-x)sec~x=sin~x\frac{1}{cos~x}=\frac{sin~x}{cos~x}=tan~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 20
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