Answer
$\frac{cos^2y}{1-sin~y}=1+sin~y$
Work Step by Step
We know that:
$sin^2y+cos^2y=1$
$cos^2y=1-sin^2y$
So:
$\frac{cos^2y}{1-sin~y}=\frac{1-sin^2y}{1-sin~y}=\frac{1^2-sin^2y}{1-sin~y}=\frac{(1+sin~y)(1-sin~y)}{1-sin~y}=1+sin~y$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 40
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