Answer
$tan(-x)~cos~x=-sin~x$
Work Step by Step
We know that:
$tan~x=\frac{sin~x}{cos~x}$
$tan(-x)=-tan~x=-\frac{sin~x}{cos~x}$
So:
$tan(-x)~cos~x=-\frac{sin~x}{cos~x}cos~x=-sin~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 34
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