Answer
$sin^2x+3~cos~x+3=-(cos~x+1)(cos~x-4)$
Work Step by Step
$sin^2x+3~cos~x+3=1-cos^2x+3~cos~x+3=-cos^2x+3~cos~x+4=-cos^2x+4~cos~x-cos~x+4=-cos~x~(cos~x-4)-1~(cos~x-4)=-(cos~x+1)(cos~x-4)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 32
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