Answer
$(sin~x+cos~x)^2=1+2~sin~x~cos~x$
Work Step by Step
Remember that: $sin^2x+cos^2x=1$
$(sin~x+cos~x)^2=sin^2x+2(sin~x)(cos~x)+cos^2x=(sin^2x+cos^2x)+2~sin~x~cos~x=1+2~sin~x~cos~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 41
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