Answer
$cos~x(1+tan^2x)=sec~x$
Work Step by Step
One of the Pythagorean Identities is:
$1+tan^2x=sec^2x$
Also:
$sec~x=\frac{1}{cos~x}~→~cos~x=\frac{1}{sec~x}$
$cos~x(1+tan^2x)=\frac{1}{sec~x}sec^2x=sec~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 15
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