Answer
$csc~u$
Work Step by Step
$cos(\frac{\pi}{2}-u)=sin~u$
$sec(\frac{\pi}{2}-u)=\frac{1}{cos(\frac{\pi}{2}-u)}=\frac{1}{sin~u}=csc~u$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.1 - Using Fundamental Identities - 7.1 Exercises - Page 513: 4
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