Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Problems by Topic - Page 748: 124b

Answer

$OH^-$ is a Lewis base.

Work Step by Step

- Drawing the Lewis structure for $OH^-$, we will see that, the oxygen has 3 lone pairs and a negative charge, therefore, it is capable of donating these electrons, making it a Lewis base. To draw this structure: - Count the total electrons: "O": 6, "H": 1, Negative charge: 1 = 8 electrons - Draw an "O" and an "H". - Make a bond between them (-2 electrons = 6) - Hydrogen has 2 electrons, so it is full already. - Put the other electrons in the oxygen. (-6 electrons = 0)
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