Answer
This solution will be "pH-neutral".
Work Step by Step
1. Analyze each type of ion in this salt, and determine which is stronger:
- $Rb^{+}$
- Strong bases have insignificant acids as conjugate pair.
- $Rb^+$ is the conjugate acid of $RbOH$, which is a strong base.
- $Rb^+$: Insignificant acid.
- $I^-$
- Strong acids have insignificant bases as conjugate pair.
- $I^-$ is the conjugate base of $HI$, which is a strong acid.
- $I^-$: Insignificant base.
Therefore: there isn't any significant electrolyte, so, the solution will be neutral.
