Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 - Applications of Vectors - 7.5 Exercises - Page 343: 58

Answer

$\theta=78.93^{\circ}$

Work Step by Step

$\textbf u $=$-5 \textbf i +12\textbf j $ $\textbf v $=$ 3 \textbf i +2 \textbf j $ $\cos\theta$=$\frac{ \textbf u . \textbf v }{ | \textbf u | | | \textbf v | } $ $\cos\theta$=$\frac{ (-5\textbf i +12\textbf j ) \cdot (3 \textbf i+2 \textbf j) }{ | -5 \textbf i +12\textbf j | | 3 \textbf i + 2\textbf j | } $ $\cos\theta$=$\frac{ -5\times 3+12 \times 2 }{ | \sqrt {(-5)^2+12^2}| | | {\sqrt { 3^2+2^2} | } }$ $\cos\theta$=$\frac{ 9 }{ ( 13) (\sqrt {13}) } $ $\theta$ $=\cos^{-1}\left(\frac{9}{13\sqrt {13}}\right)=78.93^{\circ}$
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