Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 - Applications of Vectors - 7.5 Exercises - Page 343: 53

Answer

$135^{\circ}$

Work Step by Step

$\textbf u $=$\langle 2,1 \rangle$ $\textbf v $=$\langle -3,1 \rangle$ $\cos\theta$=$\frac{ \textbf u . \textbf v }{ | \textbf u | | | \textbf v | } $ $\cos\theta$=$\frac{ \langle 2,1 \rangle . \langle -3,1 \rangle }{ | \sqrt {2^2+1^1}| | | \sqrt { (-3)^2+1^2} | } $ $\cos\theta$=$\frac{ 2\times (-3)+1\times 1 }{ | \sqrt {2^2+1^1}| | | \sqrt { (-3)^2+1^2} | } $ $\cos\theta$=$\frac{ -5 }{ | \sqrt {5}| | | \sqrt { 10} | } $ $\cos\theta$=$\frac{ -5 }{ \sqrt {50} }=\frac{-5}{5\sqrt 2}=-\frac{1}{\sqrt 2}$ $\theta$ $=\cos^{-1}\left(-\frac{1}{\sqrt 2}\right)=135^{\circ}$
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