Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 - Applications of Vectors - 7.5 Exercises - Page 343: 56

Answer

$45^{\circ}$

Work Step by Step

$\textbf u =\langle 4,0 \rangle$ $\textbf v =\langle 2,2 \rangle$ $\cos\theta=\frac{ \textbf u . \textbf v }{ | \textbf u | | | \textbf v | } $ $\cos\theta=\frac{ \langle 4,0 \rangle . \langle 2,2 \rangle }{ | \sqrt {4^2+0^2}| | | \sqrt { 2^2+2^2} | } $ $\cos\theta=\frac{ 4\times 2+0\times 2 }{ | 4| | | {\sqrt { 8} | } }$ $\cos\theta=\frac{ 8 }{ 8\sqrt 2 }=\frac{1}{\sqrt 2} $ $\cos\theta=\frac{1}{\sqrt 2}$ $\theta=\cos^{-1}\left(\frac{1}{\sqrt 2}\right)=45^{\circ}$
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