Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 - Applications of Vectors - 7.5 Exercises - Page 343: 57

Answer

$\theta=36.87^{\circ}$

Work Step by Step

$\textbf u $=$3 \textbf i +4\textbf j $ $\textbf v $=$\textbf j $ $\cos\theta$=$\frac{ \textbf u . \textbf v }{ | \textbf u | | | \textbf v | } $ $\cos\theta$=$\frac{ (3 \textbf i +4\textbf j) \cdot \textbf j }{ | 3 \textbf i +4\textbf j | |\textbf j | } $ $\cos\theta$=$\frac{ 3\times 0+4 \times 1 }{ | \sqrt {3^2+4^2}| | | {\sqrt { 0^2+1^2} | } }$ $\cos\theta$=$\frac{ 4 }{ ( 5) (1) } =\frac{4}{5} $ $\theta$ $=\cos^{-1}\left(\frac{4}{5}\right)=36.87^{\circ}$
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