Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 - Applications of Vectors - 7.5 Exercises - Page 343: 40

Answer

$\textbf {-2u+4v}$=$\langle 20,2 \rangle$

Work Step by Step

$\textbf u$=$\langle -2,5 \rangle$ $\textbf v$=$\langle 4,3 \rangle$ $\textbf {-2u+4v}=-2 \times$$\langle -2,5 \rangle$+$4\times$$\langle 4,3 \rangle$ $\textbf {-2u+4v}$=$\langle 4,-10 \rangle$+$\langle 16,12 \rangle$ $\textbf {-2u+4v}$=$\langle 4+16,-10+12 \rangle$ $\textbf {-2u+4v}$=$\langle 20,2 \rangle$
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