Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 - Applications of Vectors - 7.5 Exercises - Page 343: 44

Answer

$\langle 6,-3 \rangle$=6 $\textbf i$ -3 $\textbf j$

Work Step by Step

$\langle 6,-3 \rangle$= $\langle 6,0 \rangle$+ $\langle 0,-3 \rangle$ $\langle 6,-3 \rangle$= 6 $\langle 1,0 \rangle$-3 $\langle 0,1 \rangle$ $\langle 6,-3 \rangle$= 6 $ \textbf i $-3 $ \textbf j$
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