Answer
$-ln|cot(t)|+C$
Work Step by Step
$\int \frac{(csc(t))^2}{cot(t)}dt$
let $u=cot(t)$
$du=-(csc(u))^2dt$
$\int \frac{(csc(t))^2}{cot(t)}dt$
$=-ln|cot(t)|+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises - Page 334: 38
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