Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises - Page 334: 21

Answer

$\frac{1}{3}(ln(x))^3+C$

Work Step by Step

$\int\frac{(ln(x)^2)}{x}dx$ let u = $ln(x)$ du = $\frac{1}{x}dx$ $\int u^2 du = \frac{1}{3}u^3+C$ $=\frac{1}{3}(ln(x))^3+C$
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