Answer
$\frac{1}{3}(ln(x))^3+C$
Work Step by Step
$\int\frac{(ln(x)^2)}{x}dx$
let u = $ln(x)$
du = $\frac{1}{x}dx$
$\int u^2 du = \frac{1}{3}u^3+C$
$=\frac{1}{3}(ln(x))^3+C$
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