Answer
$3 \ln |\sin(\frac{θ}{3})|+C$
Work Step by Step
$\int cot(\frac{θ}{3})dθ$
let $u=\frac{θ}{3}$
$du=\frac{1}{3}dθ$
$dθ=3$ $du$
$\int cot(\frac{θ}{3}dθ$
$=\int cot(u) (3)du$
$=3\int cot (u)du$
$=3 ln|sin(u)| +C$
$=3 ln |sin(\frac{θ}{3})|+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises - Page 334: 31
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