Answer
$2ln|sec(\frac{1}{2}x)+tan(\frac{1}{2}x)|+C$
Work Step by Step
$\int sec(\frac{1}{2}x)dx$
let $u=\frac{1}{2}x$
$du= \frac{1}{2}dx$
$dx=2du$
$\int sec(\frac{1}{2}x)dx$
$=\int sec(u)$ $2du$
$=2\int sec(u) du$
$=2(ln|sec(u)+tab(u)|+C$
$=2ln|sec(\frac{1}{2}x)+tan(\frac{1}{2}x)|+C$