Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises - Page 334: 17

Answer

$\frac{1}{3}x^3+5ln(x-3)+C$

Work Step by Step

$\int\frac{x^3-3x^2+5}{x-3}dx$ $=\int x^2dx+5\int\frac{1}{x-3}dx$ $=\frac{1}{3}x^3+5ln(x-3)+C$
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