Answer
$\frac{1}{3}x^3+5ln(x-3)+C$
Work Step by Step
$\int\frac{x^3-3x^2+5}{x-3}dx$
$=\int x^2dx+5\int\frac{1}{x-3}dx$
$=\frac{1}{3}x^3+5ln(x-3)+C$
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