Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 314: 81

Answer

$\displaystyle \int_{0}^{\pi}\cos{\frac{x}{2}}dx = 2$

Work Step by Step

To evaluate the integral $\displaystyle \int_{0}^{\pi}\cos{\frac{x}{2}}dx$, let $u = \dfrac{x}{2}$. Then we obtain $u = \dfrac{x}{2} \longrightarrow du = \dfrac{1}{2}dx \longrightarrow 2du = dx$ Before substituting, determine the new upper and lower limits of integration Lower limit: When $x = 0$, $u = \dfrac{0}{2} = 0$ Upper limit: When $x = \pi$, $u = \dfrac{\pi}{2} $ $\displaystyle \int_{0}^{\pi}\cos{\frac{x}{2}}dx = \displaystyle \int_{0}^{\frac{\pi}{2}}\cos{u}\ 2du = \displaystyle 2\int_{0}^{\frac{\pi}{2}}\cos{u}\ du = 2 \sin{u}\Big\vert_{0}^{\frac{\pi}{2}} = 2\Big[\sin{\frac{\pi}{2}} - \sin{0}\Big] = 2\Big[ 1 - 0 \Big] = 2\Big[ 1 \Big] = 2 $
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