Answer
$\int x sin(3x^{2})$ dx = -$\frac{1}{6}cos(3x^{2})$ +c where c is an arbitrary constant
Work Step by Step
To solve this integral, we will attempt to find the derivative and antiderivative pair.
$\frac{d}{dx}cos(3x^{2})$=$-sin(3x^{2})(6x)$
$=-6x sin(3x^{2})$
Therefore, $\int x sin(3x^{2})$ dx = -$\frac{1}{6}\int-6x sin(3x^{2})$ dx
=-$\frac{1}{6}cos(3x^{2})$ +c where c is an arbitrary constant
