Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 314: 62

Answer

= $csc^{2}x$

Work Step by Step

$\frac{d}{dx}$ [$\int_{{\,0}}^{{\,x}}$ $csc^{2}t$ $dt$] = $csc^{2}x$
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