Answer
= $\frac{1}{x^{2}}$
Work Step by Step
$\frac{d}{dx}$ [$\int_{{\,1}}^{{\,x}}$ $\frac{1}{t^{2}}$ $dt$ ]= $\frac{1}{x^{2}}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Review Exercises - Page 314: 60
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