Answer
$=\frac{2(25-x^2)^{3/2}}{3}+C$
Work Step by Step
$let$ $25-x^2=u$
$du=-2x$ $dx$
$\int u^{1/2}$$du$
$=\int (25-x^2)^{1/2}$$-2x$ $dx$
$=\frac{2(25-x^2)^{3/2}}{3}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 7
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