Answer
$=\frac{(t^2+2)^{3/2}}{3}+C$
Work Step by Step
$let$ $t^2+2=u$
$du=2t$ $dt$
$\int u^{1/2}$ $du$
$=\frac{1}{2}\int (t^2+2)^{1/2}$$2t$ $dt$
$=\frac{1}{2}(\frac{2(t^2+2)^{3/2}}{3})+C$
$=\frac{(t^2+2)^{3/2}}{3}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 13
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