Answer
$-\frac{1}{3(1+x^{3})}+C$
Work Step by Step
$let$ $1+x^3=u$
$du=3x^2$ $dx$
$\int$$u^{-2}$ $du$
$=\frac{1}{3}\int$$(1+x^3)^{-2}$ $(3x^2)$ $dx$
$=\frac{1}{3}(\frac{(1+x^{3})^{-1}}{-1})+C$
$=-\frac{1}{3(1+x^{3})}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 19
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