Answer
$-(1-x^{2})^{\frac{1}{2}}+C$
Work Step by Step
$let$ $1-x^{2}=u$
$du=-2x$ $dx$
$\int$$u^{-\frac{1}{2}}$ $du$
$=-\frac{1}{2}\int$$(1-x^{2})^{-\frac{1}{2}}$ $(12x^2)$ $dx$
$=-\frac{1}{2}(2(1-x^{2})^{\frac{1}{2}})+C$
$=-(1-x^{2})^{\frac{1}{2}}+C$