Answer
$\frac{2}{9}(u^3+2)^{\frac{3}{2}}+C$
Work Step by Step
let $u^3+2=p$
$dp=3u^2 du$
$\int u^2(u^3+2)^{\frac{1}{2}}du$
$=\frac{1}{3} \int p^{\frac{1}{2}} dp$
$=\frac{1}{3}(\frac{2}{3}p^{\frac{3}{2}})+C$
$=\frac{2}{9}(u^3+2)^{\frac{3}{2}}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 16
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
