Answer
$\frac{(x^2-9)^4}{4}+C$
Work Step by Step
$let$ $x^2-9=u$
$du=2x$ $dx$
$\int u^3$$du$
$=\int (x^2-9)^3$$2x$ $dx$
$=\frac{(x^2-9)^4}{4}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 6
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