Answer
$$y' = 2x$$
Work Step by Step
$$\eqalign{
& y = {e^{\ln \left( {{x^2} + 1} \right)}} \cr
& {\text{use the inverse property }}{e^{\ln f\left( x \right)}} = f\left( x \right) \cr
& then \cr
& y = {x^2} + 1 \cr
& {\text{find the derivative}} \cr
& y' = \left( {{x^2} + 1} \right) \cr
& y' = 2x \cr} $$