Answer
$(a-1),(a+1),(a^2+1),(a^4+1)$
Work Step by Step
Given: $a^8-1$
This implies that
$=(a^4)^2-1^2$
or, $=(a^4-1)(a^4+1)$
or,$=(a^2-1)(a^2+1)(a^4+1)$
Hence, our Factors are: $(a-1),(a+1),(a^2+1),(a^4+1)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 89
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