Answer
$x^2+y^2+8x+8y+2xy+16$
Work Step by Step
Given:$(x+y+4)^2$
Apply Formula: $(a+b)^2=a^2+b^2+2ab$
This implies
$[x+(y+4)]^2=x^2+y^2+8y+16+2xy+8x$
or, $=x^2+y^2+8y+16+2xy+8x$
Hence, the result is : $x^2+y^2+8x+8y+2xy+16$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 27
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