Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 78

Answer

$x,(x-1),(x+1),(x^2+1)$

Work Step by Step

Given: $x^5-x$ or, $=x(x^4-1)$ This implies $=x[(x^2)^2-1]$ or, $=x(x^2-1)(x^2+1)$ Hence, Factors are: $x,(x-1),(x+1),(x^2+1)$
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