Answer
$x,(x-1),(x+1),(x^2+1)$
Work Step by Step
Given: $x^5-x$
or, $=x(x^4-1)$
This implies
$=x[(x^2)^2-1]$
or, $=x(x^2-1)(x^2+1)$
Hence, Factors are: $x,(x-1),(x+1),(x^2+1)$
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