Answer
$9x^2y^4-16x^2$
Work Step by Step
Given:$(3xy^2-4x)(3xy^2+4x)$
Apply Formula: $(a-b)(a+b)=a^2-b^2$
This implies
$(3xy^2-4x)(3xy^2+4x)=(3xy^2)^2-(4x)^2$
or, $=9x^2y^4-16x^2$
Hence, the result is : $9x^2y^4-16x^2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 25
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