Answer
$21x^{5}y^{4}-35x^2y^3-7xy^2$
Work Step by Step
Given:$(7xy^2)(3x^4y^2-5xy-1)$
Multiply the given polynomials.
This implies
$(7xy^2)(3x^4y^2-5xy-1)=21x^{4+1}y^{2+2}-35x^2y^3-7xy^2$
Hence, the result is : $=21x^{5}y^{4}-35x^2y^3-7xy^2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 17
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