Answer
$(2x-3),(4x^2+6x+9)$
Work Step by Step
Given: $8x^3-27$
or, $=(2x)^3-(3)^3$
This implies
$=(2x-3)[(2x)^2+3^2+3x+2x]$
or, $=(2x-3)(4x^2+6x+9)$
Hence, Factors are: $(2x-3),(4x^2+6x+9)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 77
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