Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 64

Answer

$(5x-2)(25x^2+10x+4)$

Work Step by Step

Given:$125x^3-8$ Since, $a^3-b^3=(a-b)(a^2+ab+b^2)$ Thus, $=(5x)^3-(2)^3$ or, $=(5x-2)(25x^2+(5x)(2)+4$ Hence, $(5x-2)(25x^2+10x+4)$
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